12x-x^2=40

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Solution for 12x-x^2=40 equation:


Simplifying
12x + -1x2 = 40

Solving
12x + -1x2 = 40

Solving for variable 'x'.

Reorder the terms:
-40 + 12x + -1x2 = 40 + -40

Combine like terms: 40 + -40 = 0
-40 + 12x + -1x2 = 0

Begin completing the square.  Divide all terms by
-1 the coefficient of the squared term: 

Divide each side by '-1'.
40 + -12x + x2 = 0

Move the constant term to the right:

Add '-40' to each side of the equation.
40 + -12x + -40 + x2 = 0 + -40

Reorder the terms:
40 + -40 + -12x + x2 = 0 + -40

Combine like terms: 40 + -40 = 0
0 + -12x + x2 = 0 + -40
-12x + x2 = 0 + -40

Combine like terms: 0 + -40 = -40
-12x + x2 = -40

The x term is -12x.  Take half its coefficient (-6).
Square it (36) and add it to both sides.

Add '36' to each side of the equation.
-12x + 36 + x2 = -40 + 36

Reorder the terms:
36 + -12x + x2 = -40 + 36

Combine like terms: -40 + 36 = -4
36 + -12x + x2 = -4

Factor a perfect square on the left side:
(x + -6)(x + -6) = -4

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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